Show that the kinetic energy may be written $T=\frac12m\mathbf{u\cdot((u\cdot v)v−}{r^2\mathbf{\ddot u}})$- why does $\mathbf{\dot r\cdot r}=\dot rr$?

score 152 · Answer 15 · 2017-04-23 14:50:10

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Showing that $\Phi=\frac1{4\pi\epsilon_0}\int_{r>a}\frac{\rho_1(\mathbf{x})}r\operatorname{dV}$ for potential $\Phi$ and density $\rho_1$

Published on 23 Apr 2017 - 14:50

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Show that the kinetic energy may be written $T=\frac12m\mathbf{u\cdot((u\cdot v)v−}{r^2\mathbf{\ddot u}})$- why does $\mathbf{\dot r\cdot r}=\dot rr$?

Showing that $\Phi=\frac1{4\pi\epsilon_0}\int_{r>a}\frac{\rho_1(\mathbf{x})}r\operatorname{dV}$ for potential $\Phi$ and density $\rho_1$

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