I am self-teaching myself about metric spaces (officially a physics student), and have come across the following question:
I am asked to show that the sequence $215, 2015, 20015, 200015... $converges in the $2$-adic metric on $\mathbb{Z}$.
Now the p-adic metric is that induced by the p-adic norm $||n||=p^{-k}$ where $k$ is the highest power of the prime $p$ that divides $n$ (any motivation as to why this would be a useful metric would also be appreciated...)
Now if I choose an odd integer $x=2m+1<215$, and let the terms of the above sequence be $x_n$, then clearly $x_n-x$ is divisible by $2$ for all $n$, and the 2-adic norm of $||x_n-x||$ tends to $0$ for this sequence. So any such x satisfies the condition for the convergence limit o this series, meaning that the series converges to any odd integer $<215$ in $\mathbb{Z}$? Ad yet I have seen a general proof that the convergence limit of a sequence under any metric is unique!
Note: This question has been edited so some of the initial comments no longer apply.
I don't know much about the p-adic metric but won't this sequence converge to $15$?
Namely, if $a_n$ denotes the number $20\ldots 015$, with $n$ zeros, then $a_n-15= 2\cdot 10^{n+2}= 2^{n+3} 5^{n+2}$, so $\|a_n-15\|=2^{-n-3}$.