Below is the question I'm not sure I've properly solved.
A smooth bead of mass 100g is threaded on a light inextensible string of length 70 cm. The string has one end attached to a fixed point A and the other to a fixed point B 50 cm vertically below A. The bead moves in a horizontal circle about the line AB with a constant angular speed of $\omega$ rad/s, and the string taut. If the bead is at a point C on the string with AC = 40 cm, find the value of $\omega$ and the tension in the string.
Because its a 3-4-5 triangle, I found the horizontal rotation plane to be 0.18m above B, and therefore 0.32m below A. The radius is then 0.24m. I found this by extending AC to 6.25m. I then resolve the vertical and horizontal forces and found $\omega$ to be 4.88 rad/s. I`m however not sure about this answer as books says 16.9, 4.9N.
Any help would be appreciated.
Here is an image to help.
Edit: I had the resultant of the strings at the wrong angle. Now corrected I get the same result as the book.
This should be a comment but a diagram won't post to the comments. Take a look and see if you agree.