we have AB can spin round A with angular velocity $\omega_0$. Now, how can find angular velocity of CD which is $\omega_{CD}$. With the length of $AB,BC,CD$ are fixed.
This is my effort:
Firtly, I attach a coordinate axis $OXY$ at $A$, and I find the position of $B$ and $D$ like bellow:
$x_B=AB\cos (\omega_0t)$
$y_B=AB \sin(\omega_0t)$
$x_D=AD$
$y_D=0$
Secondly, I found the position of C by two equations:
$(x_C-x_B)^2+(y_C-y_B)^2=BC^2$ and $(x_D-x_C)^2+(y_D-y_C)^2=CD^2$
and I tend to find the value of angle $\angle{CDA}$ to find $\omega_{CD}$
but I stuck at two equations above that have solution's position of $C$ because I receive 2 solutions and I don't know what is the right?
My purpose is solving this problem by Maple so i gonnna show my code:
restart;
xB := AB*cos(omega0*t);
yB := AB*sin(omega0*t);
xD := AD;
yD := 0;
pt1 := (xC-xB)^2+(yC-yB)^2 = BC^2;
pt2 := (xD-xB)^2+(yD-yC)^2 = CD^2;
solve({pt1, pt2}, [xC, yC]);
And I don't know command to choose 1 solution in maple,too.
So can you help me? Or if you have documents related about this, could you share me. Thank you so much!