EDIT: All that is required for me to understand how to graph the function, is how to determine its range
As the title implies, I am unsure of how to graph $\arccos(1/x^2)$. So far, I have found that there is an asymptote at $x=0$, and the domain is $x \ge 1$ and $x \le-1$, and that the range is $0 \le y \le \pi$, and that the function is even.
I had a pretty good idea of the graph until I plotted it onto the Desmos website, and realised that there is no asymptotic nature of $x=0$, and the range is different. Can someone please explain why this is so?
This is quite urgent, so any quick help would be appreciated.
Thanks
Hint: You have correctly identified the domain of the function, and also the fact that the range of $\arccos\theta$ is $[0,\pi]$. But for the domain you have found, what is the sign of the argument of $\arccos$? What does the fact that the argument is always positive tell you about the value of $\arccos\frac{1}{x^2}$ and therefore about the range of your function?