I always forget this result
Is cartesian product of countable set countable under finite or countable cartesian products?
Is there a good way to remember this? Like a proof sketch where the proof would go wrong if we take the product of too many countable sets?
Suppose each of your countable sets actually is $\mathbb{N}$. Then a countable product of them would have elements of the form
$$(n_0,n_1,\dots)$$
i.e. an infinite sequence of natural numbers.
Any real number in $[0,1]$ has a decimal expansion of the form
$$0.d_0d_1\dots$$
i.e. an infinite sequence of digits in $\{0,\dots,9\}$.
Since $\{0,\dots,9\}\subseteq \mathbb{N}$, there are at least as many sequences of natural numbers as there are reals in $[0,1]$, i.e. uncountably many.