Suppose $f$ and $g$ are one-to-one functions such that $f(2)=7$, $f(4)=2$, and $g(2)=5$. If possible, find the values of
A) $(g \circ f^{-1})(7)$
B) $(f \circ g^{-1})(5)$
C) $(f^{-1} \circ g^{-1})(5)$.
Suppose $f$ and $g$ are one-to-one functions such that $f(2)=7$, $f(4)=2$, and $g(2)=5$. If possible, find the values of
A) $(g \circ f^{-1})(7)$
B) $(f \circ g^{-1})(5)$
C) $(f^{-1} \circ g^{-1})(5)$.
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A) We know that $f^{-1}(7)=2$ since $f$ is one-to-one. So $g(f^{-1}(7))=g(2)=5$.
B) We know that $g^{-1}(5)=2$ since $g$ is one-to-one. So $f(g^{-1}(5))=f(2)=7$.
C) We know that $f^{-1}(2)=4$ since $f$ is one-to-one. So $f^{-1}(g^{-1}(5))=f^{-1}(2)=4$.