How do I find $x$ of this triangle

Question

I've this angle and wanna find to $x$. So I haven't seen a question which two angle wasn't given. If someone helps me it would be great. Also thank you all.

Answer 1

We can find $A\hat BE=120$ because the angles in $\triangle ABC$ must add to $180$

We can then find that $B\hat ED=180-x$ because angles on a line must add to $180$

Next we can find that $E\hat DA = 360 - (40+120+(180-x)) = 20 + x$ because angles in the quadrilateral $ABED$ must add to $360$

Now we can find that $E\hat DC = 180 - (20+x) = 160 - x$ because, again, angles on a line must add to $180$

Finally we can look at $\triangle EDC$ to see that $20 + x + 160 - x = 180$

It is obvious that the $x$ will cancel out of this equation, and therefore it is impossible to find $x$ with the given diagram

Answer 2

$$B=180-40-20=120$$ $$D=180-x-20$$

$$120+40+(180-x)+(x+20)=360$$

$$0=0$$ this proves that your question is not well-asked. is $D $ the middle of $( AC) $.