I am not exactly sure how to prove triangle inequality for this metric. For other metrics the proof was more intuitive, I hope you can help me out.
$$d(x,y) = |x-y|^{3}$$
I am not exactly sure how to prove triangle inequality for this metric. For other metrics the proof was more intuitive, I hope you can help me out.
$$d(x,y) = |x-y|^{3}$$
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Consider $x=0, z=1, $ and $y=2$.
$d(x,y)=8, d(x,z)=1, $ and $d(y,z)=1$,
so the triangle inequality is not satisfied, and your $d(x,y)$ is not a metric.