Start from the inside and work your way out. $$\min_{y\ge 0} x-y$$ is a function of $x$. However, regardless of what $x$ is, the minimum is $-\infty$ as $y$ may be arbitrarily large. Hence, $$\max_{x\ge 0}\min_{y\ge 0}x-y=\max_{x\ge 0} -\infty$$
which is just $-\infty$.
Start from the inside and work your way out. $$\min_{y\ge 0} x-y$$ is a function of $x$. However, regardless of what $x$ is, the minimum is $-\infty$ as $y$ may be arbitrarily large. Hence, $$\max_{x\ge 0}\min_{y\ge 0}x-y=\max_{x\ge 0} -\infty$$ which is just $-\infty$.