There are two blue beads and x red beads in a box. The probability that two random beads taken at random from the box are both red is 15/22, how do I work out x?
2026-03-29 12:12:01.1774786321
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How do I work out an unknown probability? (Sorry if I'm not specific enough details in main body)
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The probability of picking two red balls (by uniform picking) is:
$$p = \frac {x}{x+2} \times \frac {x-1}{x+1} = \frac {x^2 - x}{(x+2)(x+1)}.$$
You want this probability to equal $\frac {15}{22}$. Just make these two quantities equal and you find the following equation:
$$\begin{aligned} 15(x^2 + 3x + 2) &= 22(x^2-x) \\ 7x^2 - 67x - 30 &= 0 \end{aligned}$$
Which gives you the (positive) solution $x = 10$.
Hint:
There are $x+2$ beads total, hence the probability of selecting a red bead first is $\frac{x}{x+2}$
What will the probability of selecting another red bead after this be?