If $a=29$, and $b=21$, how many triangles are there such that side $c$ is a whole number?
My approach: Tried using certain equations to establish relationship between sides to maybe point to right answer, but to no avail.
How many triangles are there with whole number side?
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No equations needed. These two sides must be connected. How long or short could the third side be?
The longest is clearly when $a$ and $b$ are in a line without overlap. Their ends will be $29 + 21 = 50$ apart.
The shortest is again when they are in line but overlap. The unjoined ends will be $29 - 21 = 8$ apart.
Are these degenerate extremes triangles? You decide.
However, all of the lengths between these extremes are certainly triangles.
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A bit of geometry:
Draw $a=\overline{BC}=29;$
Draw a circle about $C$ with radius $r=21$.
$2$ Intersection points of circle with $BC$ :
1) $D_1$ where $\overline{BD_1}= 8$;
2) $D_2$ where $\overline{BD_2}=8 +2\cdot 21= 50$.
The locus of $A$ are the points on this circle.
Hence $8< c <50$, or $9 \le c \le 49$.
How many integers c with above constraints?
Since by the triangle inequality $$29+21>c$$ and $$c+21>29,$$ we obtain: $$9\leq c\leq49.$$ Can you end it now?