How much do the internal angles of the circumferences measure, which have 3 points of tangency?

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Being $A$, $B$ and $C$ points of tangency, find $x + y$.

I do not understand how to solve, since I think that $'x°'$ y $'y°$ can vary a lot, those angles can be enlarged or reduced depending on how you transcribe the drawing.

Angles

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Since $$DA=DB=DC,$$ $$\measuredangle DAB=x$$ and $$\measuredangle DCB=y,$$ we obtain: $$360^{\circ}-2x-2y=70^{\circ},$$ which gives $$x+y=145^{\circ}.$$