How to construct an n-gon by ruler and compass?

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Since $\cos[\frac{2\pi}{15}] $ is algebraic and equal to $\frac{1}{8}(1+\sqrt{5}+\sqrt{30-6\sqrt{5}})$ we know that the regular 15-gon is constructible by ruler and compass.

Although I know how to construct a hexagon by ruler and compass and have seen the construction of a pentagon done in a youtube video, I can't find a description of a general approach to constructing n-gons where $n>7$ anywhere.

Is there a general approach, geometric algorithm if you like, to constructing an n-gon by ruler and compass?

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In order to construct an angle equal to $\frac{2\pi}{15}$, you just need to construct an equilateral triangle and a regular pentagon, since: $$ \frac{2\pi}{15} =\frac{1}{2}\left(\frac{2\pi}{3}-\frac{2\pi}{5}\right).$$ Have a look at the Wikipedia page about contructible regular polygons.

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If you can read French (purely mathematical), you'll find on this page applets for the geometric construction of the pentagon, and the penta- & heptadecagons.