The Poincaré ball is $\mathcal{B}^d = \{x \in \mathbb{R}^d : \|x\|<1 \}$. Then the Poincaré model is given by the ball and the Riemannian metric tensor $$ g_x = \left(\frac{2}{1-\|x\|}\right)^2g^E$$ where $x \in \mathcal{B}^d$ and $g^E$ denotes the Euclidean metric tensor.
The hyperbolic distance metric is $$ d(u,v) = \operatorname{arcosh}\left( 1+ 2 \frac{\|u-v\|^2}{(1-\|u\|)^2(1-\|v\|)^2}\right)$$
My first question is, what is $g_x$ telling us if $d(u,v)$ is telling us the distance?
Then, I'm unsure of what the "Euclidean metric tensor" is, one source referred to a $n\times n$ identity matrix, is that it?
As a couple of examples:
(a) Convert Euclidean to Hyperbolic in $\mathbb{R}$:
$$ g_x = \left(\frac{2}{1-|x|}\right)^2$$ And the distance between $x_1$ and $x_2$ is
$$ d = \operatorname{arcosh}\left( 1+ 2 \frac{|x_1 - x_2|^2}{\left(1-|x_1|\right)^2\left(1-|x_2|\right)^2}\right) $$ (b) Convert Euclidean to Hyperbolic in $\mathbb{R}^2$:
$$ g_x = \left(\frac{2}{1-\sqrt{\sum_{i=1}^n x_i}}\right)^2\times \pmatrix{1&0\\0&1} $$
And the distance between $x$ and $y$ here is $$ d = \operatorname{arcosh}\left( 1+ 2 \frac{\sum_{i=1}^n (x_i - y_i)^2}{\left(1-\sqrt{\sum_{i=1}^n x_i}\right)^2\left(1-\sqrt{\sum_{i=1}^n y_i}\right)^2}\right) $$
Have I got the notation correct?
The Wikipedia article states
The key part is the last sentence, where the tensor can be integrated to give length of curves. Essentially it defines the differential element of arc length at any point in the space. Thus, the equation $$ g_x = \left(\frac{2}{1-\|x\|)}\right)^2g^E $$ is stating that the Euclidean and Hyperbolic tensors at a point $\,x\,$ differ by a constant factor which depends only on $\,x\,$ and not the two tangent vectors.