$$f(2x^2+3x+4)=6x^2+9x+20$$
How to solve $f(2)+f^{-1}(5)$ ?
Any help or advice on solving is much appreciated. Thanks!
2026-04-13 13:39:08.1776087548
How to find $f(2)+f^{-1}(5)$ if $f(2x^2+3x+4)=6x^2+9x+20$?
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$$f(2x^2+3x+4)=3(2x^2+3x+4)+8$$ So a simple conjecture is $f(x)=3x+8$. As $f(-1)=5,f(2)=14$; the expression to evaluate becomes $13$.