How to find one corner of an equilateral triangle in an cartesian system

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How to find the coordinates of one corner of an equilateral triangle in an cartesian system if I know the coordinates of the other two corners and the $h$ (altitude)? I need the simplest solution of them all. Thank you.

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Solve the system of the equations of the two circles centered at one point and passing through the other: $$ \begin{cases} (x-x_1)^2+(y-y_1)^2=(x_2-x_1)^2+(y_2-y_1)^2\\ (x-x_2)^2+(y-y_2)^2=(x_2-x_1)^2+(y_2-y_1)^2\\ \end{cases} $$