So the question is
$$ Y= log(-x+2)$$
So I factored as my teach told the class that $x$ can only be subtracted
so I factored out
$$ Y = log(-(x-2))$$
Information I got from the following equation
$$ a = 1$$ $$h= 2$$ $$k = 0 $$
$h = 2$ cause of the factored
so this is how I thought I would graph
if what was written in the picture wasn't clear because of resolution
Anchor point of the equation because 2 was $h$ so it has to move 2 units from the original $(3,0)$ is the anchor point. When I checked the answer I found out that I did it wrong as even if it reflected over $y$ axis, it would cross the asymtote
How would i do this?
No idea what's going on in the images but I'll go step by step as to how to graph the function.
As you already got, from this you know two things: the asymptote is equal to 2 AND the equation is reflected along the y-axis\begin{equation} y = \log (-x+2) = \log(-(x-2))\end{equation}
You find the anchor point by determining when y = 0, so \begin{equation} -x + 2 = 1 \end{equation}
Therefore, x = 1.
So to conclude, the graph should look like: https://i.stack.imgur.com/ofnjJ.png