The thing I want to input:
$$\frac{1}{n+1} + \frac{1}{n+2} + ... + \frac{1}{2n} > \frac{13}{24}, n>1$$
The best I managed so far:
But it says it's not true. I can do the first step of the proof and it's true (for n=2).
Answer for this problem:
Wolfram Alpha input and result
my question is not a duplicate, as it's about wolfram alpha not interpreting this correctly.
Wolfram Alpha gives bizarre answers... Set $S_n = \sum_{i=1}^{n} \frac{1}{n+i}$ We have $S_{n+1}- S_n = + \frac{1}{2n+1} - \frac{1}{2(n+1)} \geq 0$. Therefore $(S_n)$ is increasing. $S_2 = \frac{7}{12}>\frac{13}{24}$. Hence the result ...