How to prove [⋀(¬( → ))]⋁(⋀) ≡ p

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I need to prove this using logical equivalences but I'm stuck near the end. Here is what I've got so far.

[⋀(¬( → ))]⋁(⋀) ≡ p

[⋀(¬( → ))] ≡ p - Absorption Laws

[⋀( ⋀ ¬)] ≡ p - Conditional Laws

This is kind of where I'm stuck, I had some vague ideas but nothing that would get me to the end of the proof. Thank you for any help.

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[⋀(¬( → ))]⋁(⋀)

[⋀¬(¬ ⋁ )]⋁(⋀)

[⋀( ⋀ ¬)]⋁(⋀)

(⋀¬)⋁(⋀)

⋀(¬⋁)

⋀true