Proposition 3. If $K$ is an ordered field, then $K$ has a subfield isomorphic to $\mathbb{Q}$.
How to solve Exercise 2?
How does embedding, I suppose in meaning of embedding defined before in the post linked as order-preserving ring homomorphism, $e:\mathbb{Q}\,{\rightarrow}\,K$, imply that for all ordered fields $K$ there exists a subfield of $K$ isomorphic to $\mathbb{Q}$?
First extend $\varphi:\mathbb N\to K$ to $\psi:\mathbb Z\to K$ by $$\psi(n)\ =\ \begin{cases} \varphi(n) & \text{if} & n>0 \\\\ 0 &\text{if}& n=0 \\\\ \left(-1_K\right)\varphi(-n) &\text{if}& n<0 \end{cases}$$ Now extend $\psi:\mathbb Z\to K$ to $e:\mathbb Q\to K$ as follows: for $r\in\mathbb Q$, write $r=\dfrac mn$ where $m,n\in\mathbb Z$, $n>0$, and either $m=0$ or $\gcd(m,n)=1$; then define $$e(r)\ =\ \psi(m)\left[\varphi(n)\right]^{-1}$$ There will be a few things you need to check, such as that $\varphi(n)\ne0_K$, that $e$ preserves ordering, and so on.