In the convex pentagon ABCDE, side BC is parallel to diagonal AD and AE is parallel to BD. Points N and M bisect sides ED and CD respectively. x, y, z are the altitudes to triangles $\triangle MNQ, \triangle MND$ and $\triangle ABQ$ respectively.
How would you show that ratios $\dfrac{AB}{MN} = \dfrac{2AB}{EC}$ and $\dfrac{(x+y)}{z} $ are equal? Or what are your first thoughts/approaches here?
2026-04-01 02:53:37.1775012017
How to show equality of these ratios?
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