How do I go about simplifying this:
$$\sum_{k=1}^nk \cdot k!$$
Wolfram alpha tells me it's the same as $(n+1)!-1$ but I don't see how.
2026-04-08 16:15:21.1775664921
How to simplify $\sum_{k=1}^nk\cdot k!$
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Hint: $$k\cdot k! = [(k+1)-1]\cdot k! = (k+1)!-k!$$