Please advise on how to solve the following equation. $$ {\log_{x} 9} + {\log_{2} x} = {\log_{2} (9+x)} $$ I tried to rearrange and got this. $$ {\log_{x} 9} = {\log_{2} (1+\frac{9}{x})} $$ $$ [{\log_{9} x}][{\log_{2} (1+\frac{9}{x})}] = 1 $$ Then I got stuck.
Anyone could help on how to proceed?