A radio antenna that is 40 feet high stands on top of the Wentworth Building. From a point in front of Bailey's Drugstore, the angle of elevation of the top of the pole is 54°54'and the angle of elevation of the bottom of the pole is 47°30'.How tall is the Wentforth Building.
I think the Wentforth Building is 40-X
I have a diagram I don't think I'm right but here
Thats how angle of elevation is supposed to be right, like straight and then diagonal? I don't really know what to do after this, How am I supposed to solve this?
BD is Bailey's Drugstore and WB is Wentworth Building
Adapting the earlier diagram, consider the triangle ABC.
We know that $AB=40$, that $\angle ACB=7^{\circ}24'$ (difference between two given angles) and that $\angle CAB=35^{\circ}06'$.
Use the Sine Rule to find $BC$.
Then the height of the building is the angle opposite a $47^{\circ}30'$ angle in a right-angled triangle with hypotenuse $BC$. Just use straightforward trigonometry for that.