I’m relatively new to mathematics, and I admit I’m still trying to grasp the concept of infinity, so there might be some errors in my thinking.
I understand that $\infty$ is not a real number, which means standard mathematical operations don’t apply to it. I’ve come across the idea that there can be different magnitudes of infinity (please correct me if I’m mistaken).
$$ \infty_a > \infty_b $$
Let’s imagine 2 functions, $f_x$ & $f_y$, of time.
At a constant time, $c$,
$$f_x(c) = f_y(c)$$
From this, we can define two perpendicular line segments, $X$ and $Y$, whose midpoint is a fixed point. Their lengths are determined by $f_x$ and $f_y$, starting at the same time.
Hence, at any time $c$,
$$|X| = |Y| \text{, where } |l| = \frac{\text{length of line segment}}{2}$$
Now, let’s introduce another line, $L$, with the same properties as $X$ and $Y$, but with variable angles between $X$ or $Y$.
So, at a constant time,
$$|X| = |Y| = |L| \text{, where } |l| = \frac{\text{length of line segment}}{2}$$
According to the definition of a Cartesian plane, any line drawn from the midpoint is in the Cartesian plane till infinity. In other words it can’t be bigger than axises in magnitude that are in plane.
If we fix the maximum length of the lines, we can conclude that the plane will have the boundary shape of a circle, as the distance from the origin to the end is equal to $|X| = |Y| = |L|$.
Additionally, if time increases infinitely, we can infer that it will always form a circle.
My question is, based on the above reasoning, can we assert that the coordinate system is circular in 2D and spherical in 3D at infinity? Or is this logic only applicable to real numbers, or can we not be certain?
You're right that in some sense, the plane has the same infinite length in every direction. You could think of it as circular for this reason, but this is dubious because "infinite length" is not precise in a geometric way.
Imagine stretching the plane in the $x$-direction, taking every point $(x,y)$ to the point $(2x,y)$. The resulting set of points is the same as the original set, because every original point $(x,y)$ is obtained from a point $(\frac x2,y)$. So "stretching" does nothing to the plane as a whole. In contrast, a stretched circle is no longer a circle. There's no bounded geometric shape that remains the same when stretched, so it's misleading to think of the plane as having such a shape.
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