How would you simplify this expression involving complex numbers and a logarithm?

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The expression is

$$\log\left(\left| \frac{z+ia}{z-ia}\right|\right) $$

Here, $a>0$ is real, $i$ is the imaginary unit, and $z=x+iy$. The expression comes from extracting the imaginary part of an expression so it should end up being purely real, however I can't manage to remove the imaginary unit from any of my expressions. I know that it should end up being something like:

$$\frac{1}{2} \log\left( \frac{x^2 + (y+a)^2}{x^2 + (y-a)^2}\right)$$

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Note that $|z|=|x+iy|=\sqrt{x^2+y^2}$ when both $x$ and $y$ are assumed to be real numbers. Therefore, we have

$$\left|\frac{z+ia}{z-ia}\right|=\sqrt{\frac{x^2+(y+a)^2}{x^2+(y-a)^2}}$$

Can you finish now?