If $f_n \longrightarrow f$ almost everywhere and $g_n \longrightarrow g$ almost everywhere

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1 The Riemann function $f:[-1,1]\longrightarrow \mathbb{R}$ defined as

$$ f(x)= \begin{cases} 0, &\textrm{if }x \notin \mathbb{Q}\cap[-1,1]\textrm{ or }x =0\\ \frac{1}{q} , &\textrm{if }x\in \mathbb{Q} \cap[-1,1]\textrm{ and }x =\frac{p}{q}\neq 0 \end{cases} $$

Where $x =\frac{p}{q}$ is an irreducible fraction and q is non zero ($q\neq o)$

Does the Lebesgue Criterion for Riemann Integrability hold for this function?

[2] If $f_n \longrightarrow f$ almost everywhere and $g_n \longrightarrow g$ almost everywhere where $f,g$ are both finite valued, then show that

$f_n+g_n \longrightarrow f+g$ almost everywhere And

$f_ng_n \longrightarrow fg$ almost everywhere

MY ATTEMPT

1 YES!

$f$ is discontinuous at any rational point $x =\frac{p}{q}$ $(q \neq0)$ and continuous at any irrational point in [-1,1] and f is bounded.

Since $A= \mathbb{Q} \cap[-1,1]$ -{0}the set of discontinuous points of f. Hence $m(A)=0$

Therefore by Lebesgue Criterion for Riemann integrability $f$ is Riemann integrable on [-1,1] Hence $f$ is Lebesgue Integrable and

$\int^{1}_{-1} f(x) dx = \int_{[-1,1]} fdm=0$ because $f=0$ almost everywhere

IS this correct?

[2] I'm not sure how to approach this question. I've tried using THIS

but I am unable to see the connection if there is any at all. Never did a question like this so i'm unsure as to how to begin.