Why question:
If $f (t) = |t − 2|$, find $f (−t)$
has result: $|t + 2|$?
I don't understand it.
The notation $f(-t)$ says to take the expression for $f(t)$ and change all $t$ to $-t$. You get $$ f(-t) = |(-t)-2| = |-t-2| = |-(t+2)| = |t+2|. $$
$$f(-t)=|(-t)-2|=|(-1)(t+2)|=|-1||t+2|=|t+2|$$
$f(-t) = |-t - 2| = |-1||t + 2| = |t + 2|$.
Another way to describe the answer is:
$t + 2$ if $t \geq -2$ and $-t - 2$ if $t < -2$
because, when these two separate answers are combined, it gives the definition of $|t + 2|$.
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The notation $f(-t)$ says to take the expression for $f(t)$ and change all $t$ to $-t$. You get $$ f(-t) = |(-t)-2| = |-t-2| = |-(t+2)| = |t+2|. $$