If holes are half as large as processes, the fraction of memory wasted in holes is:
- $2/3$
- $1/2$
- $1/3$
- $1/5$
My attempt:
Somewhere it explained as:
Imagine processes as squares. If holes are also squares of half the side dimension of the processes (i.e. linear dimension is the largeness yardstick), then process area $= 4$ and hole area $= 1$. Then ratio of hole to total $= 1/5$ and you have your answer $(4)\space 1/5$ with a bunch of caveats.
Sorry, I didn't get the given solution, why processes as squares?
Can you explain it, please?
I would think of memory as linear, not planar, because of the way it is addressed. Then you have as many holes as processes, so the fraction of holes is $\frac {\frac 12}{\frac 12+1}=\frac 13$