If I purchase one ticket for a lottery game, what is my expected gain?

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We are given a total of 3,000,000 people who buys tickets for this lottery, and each ticket costs $20. The layout for the prizes is as follows:

Prize # of Winners
20 522,000
40 261,000
50 195,000
500 4,000
10,000 300
1,000,000 3
  1. Calculate the the pmf of p = amount of prize for random ticket
  2. If I purchase one ticket what is my expected gain?
  3. If I pay an extra $10 my prize is multiplied by 2. What is my expected gain if buy a ticket and pay an extra 10?

Solution: This is what I have so far.

For the pmf I have
p(20) = 522,000/3,000,000 = .174
p(40) = 261,000/3,000,000 = .087
p(50) = .065
p(500) = .00133
p(10,000) = .0001
p(1,000,000)=.000001

To calculate expected gain I know I have to add up the probabilities of winning each of the prizes less the cost. So the expected gain of the $20 prize would be 0(.174) because the cost of the ticket is 20 and so on... thus the expected gain would be:

$= 0(.174)+20(.087)+30(.065)+480(.00133)+9980(.0001)+999980(.000001).$

Is that correct? The question continues to ask:

Suppose that I continue to buy tickets until I win a prize (of any amount). After I win a prize, I will not buy any more tickets. Let T be the number of tickets that I will buy.

  1. Find the pmf of T if the tickets are not independent of each other
  2. Under the assumption of independence, what is the distribution of T? Write the pmf. How many tickets would I expect to buy?

Any suggestions for these last two questions?

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Mostly.   You forgot to include "not winning any prize", which still costs the ticket price so has a very probable negative gain.