If the number of degrees in certain angle is added to the number of grades the angle is $152$, find the angle in degrees.
My Attempt
Let $x$ be the angle. Then no of degrees in $x$ is $\dfrac {10x}{9}$.
If the number of degrees in certain angle is added to the number of grades the angle is $152$, find the angle in degrees.
My Attempt
Let $x$ be the angle. Then no of degrees in $x$ is $\dfrac {10x}{9}$.
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Note that $1^\circ=\frac{10}9^g$, so we have, when $x$ is the value in degrees, $$x+\frac{10}9x=\frac{19}9x=152$$ $$x=\frac{152×9}{19}=72$$