In a friendly game of Texas Hold ’em, four people are dealt two cards each. Considering there are 12 face cards, how many ways are there for everyone to get two face cards?
I need help on this problem. I don't know where to begin. I know the total amount of people is 4 and each get 2 cards to start so that could be $\frac{4!}{2!2!}$, then we have a total of 12 face cards distributed to 4 people and each need two. This is where I'm confused.