In a rhombus/parallelogram/trapezoid do the diagonals bisect the corner four angles at the vertices?
Is it possible to construct a non-rhombus by putting four 3-4-5 triangles where the right angle is not at the intersection of the two diagonals?
The following is a parallelogram
Is there any relationship between the four angles formed at the intersection of the diagonals of a parallelogram and the four corner angles at the vertices of the figure?
Is this true or false, "The four angles formed at the intersection of the diagonals of a parallelogram are congruent." When is it true or false?