For example, in what ways can I factor a conditional density of the type $f(x,y|p,q)$?
If $x$ and $y$ are independent, is it true that $f(x,y|p,q)=f(x|p,q)f(y|p,q)$?
How about $f(x,y|p,q)=f(x|y,p,q)f(y)$, is this true?
For example, in what ways can I factor a conditional density of the type $f(x,y|p,q)$?
If $x$ and $y$ are independent, is it true that $f(x,y|p,q)=f(x|p,q)f(y|p,q)$?
How about $f(x,y|p,q)=f(x|y,p,q)f(y)$, is this true?
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In general you can factor a joint density as $$ f(x, y) = f(x \mid y)f(y) $$ In a similar way, therefore, $$ f(x, y \mid p) = f(x \mid y, p)f(y\mid p) $$ And $$ f(x, y \mid p, q) = f(x \mid y, p, q)f(y \mid p, q) $$ So to critique the examples you gave, you don't have $$ f(x, y \mid p, q) = f(x \mid p, q)f(y \mid p, q) $$ unless $x$ and $y$ are conditionally independent – i.e. it doesn't suffice that they are independent. You also don't have $$ f(x, y \mid p, q) = f(x \mid y, p, q)f(y) $$ unless $f(y \mid p, q) = f(y)$, i.e. $y$ is independent of $p, q$.