Inclusion exclusion problem multiple choice and union

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7 Cards are drawn from a pack of cards (52) no returns.
Defining these events:
S - not getting spades in those 7 cards
H - not getting hearts in those 7 cards
D - ' ' diamonds ' ' ' '
C - ' ' clubs ' ' ' '

What is the probability: $P(S \cup H \cup D \cup C)$ mean?

1) probability that all the events are chosen in the 7 cards
2) probability that at least one event is chosen in 7 cards.

Because it's union, it seems right the $1$ is correct however it's literally impossible that 7 cards are picked and all of them have no shape?! I mean, 7 cards are drawn and no hearts diamond clubs and spades?! that's impossible!
However I am not sure...
Thanks for your help!

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If $A$ and $B$ are events, $P(A \cup B)$ is the probability that $A$ happens or that $B$ happens. So $P(S \cup H \cup D \cup C)$ is the probability that there is some suit that doesn't show up ever in the 7 cards.