For a question in geometry I was led to the following questions on hypergeometric functions. For $a>0$, let $$h_a(x)={}_2F_1(a i, -a i; 1; x)$$ where $i$ is a root of $-1$. Here $h_a(1)=\frac{\sinh a}{a}$ is well-defined. Consider $f(x)=x(1-x)h_a'(x)$ which is $=0$ at $x=0, 1$. Is it true that there exists a uniform constant $C$ such that for all $a>0$, $$f(x)=\frac{x(1-x)h_a'(x)}{h_a(x)} <C$$ for all $x \in [0,1]$? Numerically, I have used SageMath for $a \leq 500$ and this ratio seems to be quite small. If not true, it is possible to derive the growth rate of the ratio with respect to the coefficient $a$?
I have tried many formulas for hypergeometric functions (Contiguous Relations) in this book Special Functions without success. I also have tried just plain Taylor expansion and it is difficult to see any bounds. Thank you very much!
There is something that I do not understand. $$f_a(x)=a^2x(1-x)\frac{\, _2F_1(1-i a,1+i a;2;x)}{\, _2F_1(-i a,i a;1;x)}$$ For large values of $a$, the maximum of the function is attained closer and closer to $x=\frac 12$.
Using this asymptotic value $$f_a\left(\frac{1}{2}\right) = \frac a 2 -\frac 14+O\left(\frac{1}{a}\right)$$ which seems also to be true for $f_a\left(x_{\text{max}}\right)$
For example, $$a=2 \implies x_{\text{max}}=0.530676 \implies f_2\left(x_{\text{max}}\right)=0.767445$$ $$a=3 \implies x_{\text{max}}=0.513503 \implies f_3\left(x_{\text{max}}\right)=1.264525$$