How would one find the x-intercept and y-intercept of the line with the equation $x-2y=0$?
2026-03-25 18:45:18.1774464318
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Intercept of a Line problem
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Finding intercepts
The $x$ intercept of a line is the point on the line (if it exists) at which the y-coordinate is $0$. Thus to find this point we just set $y = 0$ in the equation of the line: $$ x - 2(0) = 0\\ \Rightarrow x = 0 $$
Hence the $x$-coordinate of the $x$-intercept is $0$. See if you can figure out how to find the $y$-coordinate of the $x$-intercept.
Finding the slope
The slope of a line can be found if we know two points which lie on the line. If we first find the $y$-intercept and call it $(x_1, y_1)$ and then the $x$-intercept and call it $(x_2, y_2)$, then the slope is given by $$ m = \frac{y_2 - y_1}{x_2 - x_1} $$
The $x$ intercept occurs when $y=0$.
The $y$ intercept occurs when $x=0$.
Can you proceed?