Is a extension of a premeasure preserves outer-measure generated by the premeasure?

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I have proved the follow:

Let $X$ be a set.

Let $S$ be a semi-ring of subsets of $X$.

Let $\mu$ be a premeasure on $S$.

Let $\overline{\mu}$ be a premeasure on a ring generated by $S$ which extends $\mu$.

Then the outer measures induced by each are identical.

So a natural question arose here:

Question

Let $X$ be a set

Let $R$ be a ring of subsets of $X$.

Let $\mu$ be a premeasure on $R$.

Let $\Sigma$ be the $\sigma$-algebra generated by $R$.

Let $\overline{\mu}$ be a measure on $\Sigma$ which extends $\mu$

Are the outer measures induced by each the same? If not, is it true when $\mu$ is $\sigma$-finite?

I guess this is not true since $\Sigma$ cannot be reached by $R_{\sigma \delta ...}$ (countable times), but i cannot think of a counterexample