Is it $E[\mathbf{1}_{\{\tau\leq T\}}]\leq E[\mathbf{1}_{\{\tau\leq T+1\}}]$?

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Consider $\{X_t\}$, a Cox process with $X_0=0$ and intensity $\lambda_t$.

Let $\tau$ be a stopping time on a compact interval $[0,T]$ such that $\tau\equiv\inf\{t>0:X_t=1\},$ (e.g. the first time a light bulb goes out).

Consider the comparison between $E[\mathbf{1}_{\{\tau\leq T\}}]$ and $E[\mathbf{1}_{\{\tau\leq T+1\}}]$, where the expectation is defined with respect to a well-defined probability space.

Is the following proof attempt valid? If not, where is it incorrect?

My claim: $E[\mathbf{1}_{\{\tau\leq T\}}]\leq E[\mathbf{1}_{\{\tau\leq T+1\}}]$.

Proof:

$E[\mathbf{1}_{\{\tau\leq T\}}]=\int \mathbf{1}_{\{\tau(\omega)\leq T\}}dP(\omega)=P(\{\tau\leq T\})$.

$E[\mathbf{1}_{\{\tau\leq T+1\}}]=\int \mathbf{1}_{\{\tau(\omega)\leq T+1\}}dP(\omega)=P(\{\tau\leq T+1\})$.

By monotonicity, $P(\{\tau\leq T\})\leq P(\{\tau\leq T+1\})$.

$\therefore E[\mathbf{1}_{\{\tau\leq T\}}]\leq E[\mathbf{1}_{\{\tau\leq T+1\}}]$.