I'm wondering if squaring using a dot product is correct. For example, let $a,b,c$ be vectors if $(a+b) = c$ then does squaring it mean that $(a+b) \cdot (a+b) = c \cdot c$ i.e does $(a \cdot a+2a \cdot b+b \cdot b) = c \cdot c$
2026-04-24 09:38:45.1777023525
Is it possible to square vector like this?
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Well, examine it in Cartesian coordinate form.
Because $a + b = c$, we have $$a_i + b_i = c_i \tag{1}\label{1}$$ where subscript $i$ indicates the coordinate component. For 2D, we have $i = 1, 2$ for $x$ and $y$ axes; for 3D, $i = 1, 2, 3$ for $x$, $y$, and $z$ axes; and so on.
For $(a + b) \cdot (a + b) = c \cdot c$ we have $$\sum_i (a_i + b_i)^2 = \sum_i c_i^2 \tag{2}\label{2}$$
If we substitute $\eqref{1}$ into $\eqref{2}$, we see that it is obviously true: both sides become the same expression.