Let $F$ be a field with $(char(F),p)=1$ or $char(F)=0$ containing the roots of unity of order $p$. Consider the following extension of $F$: $$F[a_1 ^{1/p},...,a_k ^{1/p}]$$ and assume $a_i\notin(F^*)^p$. One can prove that the polynomials $f_i(x)=x^p-a_i$ are either irreducible or they split. Indeed, every extension in the tower is galois both over $F$ and over the previous extension. My question is whether the final extension is a Kummer (abelian) extension over $F$?
It is abelian over the $(k-1)$ extension, and from the fundamental theorem of Galois extensions, for every $i=1,..,k-1$ $Gal(F[a_1 ^{1/p},...,a_{i+1} ^{1/p}]/F)$ is normal in $Gal(F[a_1 ^{1/p},...,a_{k} ^{1/p}]/F)$. However this a group $G$ can have a normal abelian subgroup $N$ and an abelian quotient $G/N$ without being abelian. I would like to understand why (and if) is $F[a_1 ^{1/p},...,a_k ^{1/p}]/F$ abelian.
Nothing wrong with Lord Shark's answer, just adding a different way of arriving at the conclusion.
Because the $a_i$s are all in $F$ you can adjoin their $p$th roots in any which order you want. This freedom forces the big extension to be Abelian. We can do it by induction $k$: