Let $f:X\to Y$ be a continuous map between metric spaces. Then $f(X)$ is a complete subset of $Y$ if
the space $X$ is compact
the space $Y$ is compact
the space $X$ is complete
the space $Y$ is complete
My trial : i was taking $X =Y =R$,,and i know that R is complete as complete map to complete so the correct option will option 3 that is the space X is complete .
Is my answer is correct or not ? pliz verified and tell me the solution i would be more thankful...
If $X$ is compact, then $f(X)$ is compact too and therefore complete.
All other options are false. Can you see why?