Is there an odd function $g$ over the reals such that $g(0)\ne0$

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Is there an odd function $g$ on domain $\mathbb{R}$, where $g(0)$ isn't equal to $0$ ?

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Hint. Note that if $g$ is odd and it is defined at $0$ then $g(0)=-g(-0)=-g(0)$.

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Any odd function on $\Bbb R$ is a symmetric curve about the origin...and if $g(0)$ is not equal to zero,then $0$ must have to two images..and that will contradict the statement of a function.....so answer is NOT.