We have that $F\leq K\leq N$ and
$G=\text{Gal}(N/F)=\{\sigma \in G : \sigma (x)=x, \forall x\in F\} \\ H=\text{Gal}(N/K)=\{\sigma \in G : \sigma (x)=x, \forall x\in K\}$
Does it hold that $$\bigcap_{\sigma \in G}\sigma H\sigma^{-1}\leq H$$ ?
We have that $F\leq K\leq N$ and
$G=\text{Gal}(N/F)=\{\sigma \in G : \sigma (x)=x, \forall x\in F\} \\ H=\text{Gal}(N/K)=\{\sigma \in G : \sigma (x)=x, \forall x\in K\}$
Does it hold that $$\bigcap_{\sigma \in G}\sigma H\sigma^{-1}\leq H$$ ?
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Yes, it is always true, not only in Galois groups. The core of $\;H\;$ , that intersection you wrote, is characterized by being a subgroup of $\;G\;$ which is maximal wrt being normal in $\;G\;$ and contained in $\;H\;$