Do the points $A(6,4)$, $B(4,-3)$, and $C(-2,3)$ form an isosceles triangle or a right triangle? How do you know?
I tried converting these to polar coordinates..
Hint: Compute $$AB=\sqrt{(4-6)^2+(-3-4)^2}=…$$ $$BC=\sqrt{(-2-4)^2+(3-(-3))^2}=…$$
$$AB=\sqrt{(4-6)^2+(-3-4)^2}=\sqrt{53}\\BC=\sqrt{(-2-4)^2+(3-(-3))^2}=\sqrt{72}\\AC=\sqrt{(-2-6)^2+(3-4)^2}=\sqrt{65}$$This is not a right triangle because $a^2+b^2\ne c^2$.
This not an isosceles triangle because no two sides are equal.
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Hint: Compute $$AB=\sqrt{(4-6)^2+(-3-4)^2}=…$$ $$BC=\sqrt{(-2-4)^2+(3-(-3))^2}=…$$