Problem
Two isosceles right triangles, one larger ($\triangle ABC$) than the other ($\triangle DEF$), superimposed such that the smaller fits completely within the boundary of the larger.
However, $\triangle DEF$ should be sized and placed such that the following constraints are met for a given $\triangle ABC$:
- $DE$ is a fixed distance, $h$ from $AB$
- $EF$ is a fixed distance, $g$ from $BC$
- $DF$ is a fixed distance, $i$ from $AC$
It is simple to calculate $E$ but I'm struggling to calculate the coordinates for $D$ and $F$.
- $D(h, ?)$
- $E(h, g)$
- $F(?, g)$
Alternatively, given the offset $E$, what should be the lengths of $DE$ and $EF$ to satisfy the constraint for distance $i$.
Summary
For a given outer isosceles right triangle, $\triangle ABC$, I wish to define an inner isosceles right triangle, $\triangle DEF$, where the distance between all parallel sides are also given.
Geometric dilation works where the distances are all equal but I haven't found an analytical solution for where they are all different.
Application
I am trying to produce a parameterized CAD drawing of a hollow triangular shaped box, where the thickness of each wall can be different and defined for any size box (using OpenSCAD).
Take a look at the figure below:
Here, I used the OP's notations. The key to the solution is that $\alpha=45^{\circ}.$ Since $\cos(\alpha)=\frac1{\sqrt2}$, $$m=\sqrt2\ i.$$ That is the equation of $e$ is
$$y=-x+10-\sqrt2\ i.$$
It is easy, then, to find the intersection points sought for. For example, in the case of point $D$, we have $x=1$ and $y=-x+10-\sqrt 2\ i$, so $E=\big(1,9-\sqrt 2\ i\big)$.