Levy's characterisation of Brownian motion

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Is there a way to break the proof of the multidimensional characterisation of BM down to the one-dimensional case?

If we have $[M^{(i)},M^{(j)}]= \delta_{ij}t$ then each $M^{(i)}$ is already a BM and has vanishing cross-brackets with the other ones. How can I quickly obtain their independence?