Through a given point inside an angle find a line cutting off a triangle of given perimeter.
From what I understand we are given some length $d$ (say via a pair of points $X,Y$ at distance $d$). Moreover we are given an angle with vertex $V$ formed by halflines $k,l,$ and a point $A$ inside it. So we are supposed to find (using a ruler and a compass) a line through $A$ intersecting $k,l$ in points $B,C$ such that the perimeter of the triangle $BCV$ (that is $|BC|+|CV|+|VB|$) equals $d$.
Any hints
Thanks