If $T:\mathbb{R}^n \rightarrow \mathbb{R}^n$ is a linear transformation, then there exists a basis for $\mathbb{R}^n$ in which $T$ is diagonal.
Is this true or false
If $T:\mathbb{R}^n \rightarrow \mathbb{R}^n$ is a linear transformation, then there exists a basis for $\mathbb{R}^n$ in which $T$ is diagonal.
Is this true or false
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No, assume $T$ represented by (in standard basis) $$\begin{pmatrix}1&1\\0&1\end{pmatrix}$$
There is no basis in which this matrix is diagonal.